EST. 2024 · LONDON·MMXXVI SPECIFICATION
AQA·Edexcel·OCR|Foundation + Higher
Ratio, Proportion & Rates of Change

Sheet № 198 · Foundation + Higher · AQA · Edexcel · OCR

198

Velocity-Time Graphs –

Velocity-time graphs are tested on both Foundation and Higher GCSE Maths papers and link algebra, geometry, and real-world problem solving. Understanding how to read and interpret them is essential for questions involving speed, acceleration, and distance.

§Key definitions

Question:

A car accelerates from rest to 20 m/s in 10 seconds, then travels at constant speed for 15 seconds. Find the total distance.

Answer:

400 metres

Q1 (Foundation):

An object accelerates from rest to 30 m/s in 6 seconds. Find the acceleration.

Q2 (Foundation):

A train travels at 40 m/s for 20 seconds. Find the distance covered.

Q3 (Higher):

A car accelerates from 10 m/s to 25 m/s in 6 seconds, then decelerates to rest in 10 seconds. Find the total distance.

§Formulas to memorise

Acceleration = gradient = change in velocity / change in time

Distance = area under the velocity-time graph

Area of triangle = ½ × base × height, Area of trapezium = ½ × (a + b) × h

To find acceleration, calculate the gradient of the relevant section: rise / run = change in velocity / change in time.

Worked example

A car accelerates from rest to 20 m/s in 10 seconds, then travels at constant speed for 15 seconds. Find the total distance.

Working:

Common mistakes

  • Confusing velocity-time graphs with distance-time graphs. On a velocity-time graph, a horizontal line means constant speed, not being stationary. On a distance-time graph, a horizontal line means stationary.
  • Forgetting to halve the area for triangular sections. A triangular section is ½ × base × height, not base × height.
  • Using the wrong units. Acceleration is measured in m/s² (metres per second squared), not m/s.

Exam tips

  • Label each section of the graph (acceleration, constant speed, deceleration) before calculating.
  • Use a trapezium when the graph goes from one velocity to a different velocity over a time period — area = ½ × (v₁ + v₂) × t.
  • If the question asks for deceleration, give a positive value. Deceleration is the magnitude of negative acceleration.
MMXXVI specification · AQA · Edexcel · OCRgcsemathsai.co.uk/formulas/velocity-time-graphs