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Algebra · Foundation & Higher

Quadratic graphs

A quadratic graph has the equation y = ax² + bx + c and produces a parabola (U-shape if a > 0, ∩-shape if a < 0). You need to draw them by completing a table of values and identify key features.

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Key facts to remember

  • 1Quadratic graphs are parabolas — symmetrical U or ∩ shapes.
  • 2The graph crosses the y-axis where x = 0 (substitute x = 0 to find the y-intercept).
  • 3It crosses the x-axis where y = 0 (the roots of the quadratic).
  • 4The turning point (vertex) lies on the line of symmetry x = −b/(2a).
  • 5If a > 0, the parabola opens upward (minimum point); if a < 0, it opens downward (maximum point).
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Formulas

Line of symmetry
x = −b / (2a)

For y = ax² + bx + c

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Worked examples

Example 1

Complete a table of values for y = x² − 3x + 2 for x = 0 to 4, and state the roots.

Working

  1. x = 0: y = 0 − 0 + 2 = 2
  2. x = 1: y = 1 − 3 + 2 = 0
  3. x = 2: y = 4 − 6 + 2 = 0
  4. x = 3: y = 9 − 9 + 2 = 2
  5. x = 4: y = 16 − 12 + 2 = 6
  6. Roots (where y = 0): x = 1 and x = 2
AnswerRoots at x = 1 and x = 2
Example 2

Find the coordinates of the turning point of y = x² − 4x + 1.

Working

  1. Line of symmetry: x = −(−4) / (2 × 1) = 4/2 = 2
  2. y at x = 2: y = 4 − 8 + 1 = −3
  3. Turning point is (2, −3)
Answer(2, −3)
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Common mistakes

Arithmetic errors when substituting negative x values (remember (−2)² = 4, not −4).
Drawing a V-shape instead of a smooth curve — quadratics are smooth parabolas.
Not plotting enough points to identify the turning point accurately.
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Exam tips

Always substitute carefully, especially with negative values — show each substitution step.
Plot at least 5–7 points and join with a smooth curve, not straight lines.

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