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Direct Proportion Equations –

GCSEMathsAI Team·7 min read·23 May 2026

Direct proportion equations are a Higher-tier topic that links algebra with ratio and proportion. When two quantities are directly proportional, one is always a constant multiple of the other. Understanding how to set up, find, and use the equation connecting them is essential for securing marks on this topic.

What Is Direct Proportion?

Two quantities are in direct proportion when one quantity is always the same multiple of the other. If y is directly proportional to x, then doubling x also doubles y, tripling x triples y, and so on.

The proportionality symbol ∝ is used to express this relationship. Writing y ∝ x means "y is directly proportional to x". To turn this into an equation, introduce a constant of proportionality, k, giving y = kx. Once you know k, you can find y for any value of x, or x for any value of y.

Direct proportion does not only apply to y ∝ x. At Higher tier you must also handle y ∝ x², y ∝ x³, y ∝ √x, and other variations. In each case, the method is the same: replace ∝ with = k, use a given pair of values to find k, then write the final equation.

Key Formulas

y ∝ x gives y = kx
y ∝ x² gives y = kx²
y ∝ √x gives y = k√x

Step-by-Step Method

  1. Write the proportionality statement using ∝ (e.g., y ∝ x²).
  2. Replace ∝ with = k to form the equation (e.g., y = kx²).
  3. Substitute the given pair of values to find k.
  4. Rewrite the equation with the value of k.
  5. Use the equation to answer the question.

Worked Example 1 — Foundation Level

Question: y is directly proportional to x. When x = 4, y = 20. Find y when x = 7.

Working: y ∝ x, so y = kx. Substitute x = 4, y = 20: 20 = k × 4, so k = 5. Equation: y = 5x. When x = 7: y = 5 × 7 = 35.

Answer: y = 35.

Worked Example 2 — Higher Level

Question: y is directly proportional to x². When x = 3, y = 36. Find y when x = 5.

Working: y ∝ x², so y = kx². Substitute x = 3, y = 36: 36 = k × 9, so k = 4. Equation: y = 4x². When x = 5: y = 4 × 25 = 100.

Answer: y = 100.

Worked Example 3 — Exam Style

Question: The cost C of a diamond is directly proportional to the square of its weight w grams. A diamond weighing 2 g costs £600. Find the cost of a diamond weighing 3.5 g.

Working: C ∝ w², so C = kw². Substitute w = 2, C = 600: 600 = k × 4, so k = 150. Equation: C = 150w². When w = 3.5: C = 150 × 12.25 = £1,837.50.

Answer: The diamond costs £1,837.50.

Common Mistakes

  • Forgetting to square (or square-root) x before substituting. If y ∝ x², the equation is y = kx², not y = kx. Read the proportionality statement carefully.
  • Using the wrong type of proportion. Direct proportion means y = kx^n; inverse proportion means y = k/x^n. Check whether y increases or decreases as x increases.
  • Not finding k first. Some students try to jump directly to the answer. Always find k explicitly — it earns method marks and prevents errors.

Exam Tips

  • Always write the proportionality statement and the equation with k as separate lines. Examiners award marks for each step.
  • If the question says "y is proportional to the square root of x", write y ∝ √x, then y = k√x.
  • Check your answer makes sense: if y is proportional to x² and x increases, y should increase by a larger factor.

Practice Questions

Q1 (Foundation): y is directly proportional to x. When x = 6, y = 15. Find y when x = 10.

Answer: y = kx. 15 = 6k, so k = 2.5. y = 2.5 × 10 = 25.

Q2 (Foundation): y ∝ x. When x = 8, y = 24. Find x when y = 42.

Answer: y = kx. 24 = 8k, so k = 3. 42 = 3x, so x = 14.

Q3 (Higher): y is directly proportional to the cube of x. When x = 2, y = 48. Find y when x = 3.

Answer: y = kx³. 48 = k × 8, so k = 6. y = 6 × 27 = 162.

Practise direct proportion equations with instant feedback — completely free on GCSEMathsAI.

Summary

  • Direct proportion means one quantity is a constant multiple of another.
  • Replace ∝ with = k to form the equation, then find k using given values.
  • Common forms include y = kx, y = kx², y = kx³, and y = k√x.
  • Always find k first, write the full equation, then substitute to answer the question.
  • Check your answer is consistent with the type of proportion described.

Test your understanding

5 quick MCQs to identify any misconceptions on this topic.

Take Diagnostic Quiz
§Academic References

Further reading from leading academic institutions — free and open-access.

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Equations & IdentitiesNRICH

Cambridge challenges on forming and solving equations.

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Solving EquationsCorbett Maths

Step-by-step methods for linear and more complex equations.

Corbett Maths · Free · Open Access
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Ratio & ProportionNRICH

Cambridge problem-solving with ratio and proportion.

University of Cambridge · Free · Open Access
C
RatioCorbett Maths

Simplifying, sharing in a ratio, and proportion problems.

Corbett Maths · Free · Open Access
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